Supernet question

Thank you very much. I understood these. Thanx a lot..

Can i ask something else?
"Class C networks 192.168.32.0 and 192.168.33.0 could
be combined to create 192.168.32.0/23."

Can these be solved like:

2^n=2 -> n=1 bit

Default sm c class: 255.255.255.0
New sm: 255.255.11111110.00000000
Dec: 255.255.254.0

or its wrong? I was having exams 2 hours ago.. the first part was like the one you solved... and the other was like the one i solve here. I suppose its correct? He will give me the half exercise correct I didnt saw this on time... but its ok. thank you.

Looks good to me

thank you:) and how can i understand when to use your way or my way? my way is correct for the /23 but not for the /24.

I have always done it by finding the step, then its easy to find the start of each subnet.

/24 will move to the next octet for the host addresses so its not really needed because you are dealing with the whole octect.