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TOPIC: subnetting class B address 172.0.0.0

subnetting class B address 172.0.0.0 11 years 4 months ago #9194

I have a class B address of 172.0.0.0 and i need 5 subnets out of it.so please help me out with this.thank you.
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subnetting class B address 172.0.0.0 11 years 4 months ago #9195

  • Rocco5757
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Hai kampala,

This is ballu. Kampala before giving reply to your query about subnetting i would like to tell you to know how to mail a message in proper format!!!!!!!!!!!!! this keeps you away from MNC's to work in and you no? i really got upset even to give reply to your mail after seeing your mail.I think u will learn how to mail others in good format.

Ok you have 172.0.0.0 network right.

Default network Mask for ur class B network = 255.255.0.0

this mask is only used to identify ur 172.0.0.0 network by a router to route a ip datagram destined to that network(172.0.0.0)

In binary notation= 11111111.11111111.00000000.00000000

Now follow as i told

From the above subnet mask u have ---

Number of hosts for the network = 2^16 = 64K approx..

i think u don't want that many hosts for ur network!!!!!!!

So what u and i do subnet the network according to requirment ok:-) fine.

Know consider the last 2 octats from our default netwok mask i.e --


00000000.00000000
(3rd octat) ( 4th octat)

now i write like this(only for ur easy understanding):

10000000.00000000

keep in mind that number of subnets = 2^(number of 1's in last 2 octats) -2.

so as i change MSB to 1, number of subnets = 2^1 = 2-2=0 , not required.

we shall try for other combination i .e 11000000.00000000

now number of subnets = 2^2 = 4-2 = 2 still not required :-)

again we try for other combination(ofcourse i know only to try & try untill i get the things to be done:-)))) i.e 11100000.00000000

now number of subnets = 2^3 = 8 - 2 =6 yes...... i got

now i have 6 subnets in that i use only 5 ....... thats.....

now combining all we get :

11111111.11111111.11100000.0000000(255.255.224.0)

This is the custom subnet mask of ur subneted netwok 172.0.0.0

i.e

172.0.0.0(only for netwok address)

172.0.32.0
172.0.64.0
172.0.96.0
172.0.128.0
172.0.160.0
172.0.192.0
172.0.224.0(only for broadcast for ur subneted network)

And number of hosts per subnet is 2^13.

This how subnet caluculations 'should' be


ok hope u got me!

regards
ballu
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