This is ballu. Kampala before giving reply to your query about subnetting i would like to tell you to know how to mail a message in proper format!!!!!!!!!!!!! this keeps you away from MNC's to work in and you no? i really got upset even to give reply to your mail after seeing your mail.I think u will learn how to mail others in good format.
Ok you have 18.104.22.168 network right.
Default network Mask for ur class B network = 255.255.0.0
this mask is only used to identify ur 22.214.171.124 network by a router to route a ip datagram destined to that network(126.96.36.199)
In binary notation= 11111111.11111111.00000000.00000000
Now follow as i told
From the above subnet mask u have ---
Number of hosts for the network = 2^16 = 64K approx..
i think u don't want that many hosts for ur network!!!!!!!
So what u and i do subnet the network according to requirment ok:-) fine.
Know consider the last 2 octats from our default netwok mask i.e --
(3rd octat) ( 4th octat)
now i write like this(only for ur easy understanding):
keep in mind that number of subnets = 2^(number of 1's in last 2 octats) -2.
so as i change MSB to 1, number of subnets = 2^1 = 2-2=0 , not required.
we shall try for other combination i .e 11000000.00000000
now number of subnets = 2^2 = 4-2 = 2 still not required
again we try for other combination(ofcourse i know only to try & try untill i get the things to be done:-)))) i.e 11100000.00000000
now number of subnets = 2^3 = 8 - 2 =6 yes...... i got
now i have 6 subnets in that i use only 5 ....... thats.....
now combining all we get :
This is the custom subnet mask of ur subneted netwok 188.8.131.52
184.108.40.206(only for netwok address)
220.127.116.11(only for broadcast for ur subneted network)
And number of hosts per subnet is 2^13.
This how subnet caluculations 'should' be
ok hope u got me!
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