From these network numbers, it's easy enough to look at the IP addresses that you listed and decide which are valid host addresses rather than network or broadcast addresses.
Did not get that paragraph.
Thanks
I'll answer that specific question.
255.255.255.224 has 27 network bits, remaining with 5 host bits.
This translates to 2^5 = 32 hosts per subnet.
hence;
x.y.z.0
x.y.z.32
x.y.z.64
x.y.z.96
x.y.z.128
x.y.z.160
x.y.z.192
x.y.z.224
Each subnet has a total of 32 ip addresses but only 30 ip addresses are usable. This is because the 1st address of each subnet is the subnet I.D and the last address of each subnet is the broadcast.
In subnet 1: x.y.z.0
x.y.z.0 is the subnet I.D and x.y.z.33 is the broadcast address
In subnet 2: x.y.z.32
x.y.z.32 is the subnet I.D and x.y.z.63 is the broadcast address
This goes the same for all the other subnets.
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